3.5.22 \(\int \frac {x}{(c+\frac {a}{x^2}+\frac {b}{x})^2} \, dx\) [422]

3.5.22.1 Optimal result
3.5.22.2 Mathematica [A] (verified)
3.5.22.3 Rubi [A] (verified)
3.5.22.4 Maple [A] (verified)
3.5.22.5 Fricas [B] (verification not implemented)
3.5.22.6 Sympy [B] (verification not implemented)
3.5.22.7 Maxima [F(-2)]
3.5.22.8 Giac [A] (verification not implemented)
3.5.22.9 Mupad [B] (verification not implemented)

3.5.22.1 Optimal result

Integrand size = 16, antiderivative size = 196 \[ \int \frac {x}{\left (c+\frac {a}{x^2}+\frac {b}{x}\right )^2} \, dx=-\frac {b \left (3 b^2-11 a c\right ) x}{c^3 \left (b^2-4 a c\right )}+\frac {\left (3 b^2-8 a c\right ) x^2}{2 c^2 \left (b^2-4 a c\right )}-\frac {b x^3}{c \left (b^2-4 a c\right )}+\frac {x^4 (2 a+b x)}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}+\frac {b \left (3 b^4-20 a b^2 c+30 a^2 c^2\right ) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{c^4 \left (b^2-4 a c\right )^{3/2}}+\frac {\left (3 b^2-2 a c\right ) \log \left (a+b x+c x^2\right )}{2 c^4} \]

output
-b*(-11*a*c+3*b^2)*x/c^3/(-4*a*c+b^2)+1/2*(-8*a*c+3*b^2)*x^2/c^2/(-4*a*c+b 
^2)-b*x^3/c/(-4*a*c+b^2)+x^4*(b*x+2*a)/(-4*a*c+b^2)/(c*x^2+b*x+a)+b*(30*a^ 
2*c^2-20*a*b^2*c+3*b^4)*arctanh((2*c*x+b)/(-4*a*c+b^2)^(1/2))/c^4/(-4*a*c+ 
b^2)^(3/2)+1/2*(-2*a*c+3*b^2)*ln(c*x^2+b*x+a)/c^4
 
3.5.22.2 Mathematica [A] (verified)

Time = 0.18 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.83 \[ \int \frac {x}{\left (c+\frac {a}{x^2}+\frac {b}{x}\right )^2} \, dx=\frac {-4 b c x+c^2 x^2+\frac {2 \left (2 a^3 c^2+b^5 x+a b^3 (b-5 c x)+a^2 b c (-4 b+5 c x)\right )}{\left (b^2-4 a c\right ) (a+x (b+c x))}+\frac {2 b \left (3 b^4-20 a b^2 c+30 a^2 c^2\right ) \arctan \left (\frac {b+2 c x}{\sqrt {-b^2+4 a c}}\right )}{\left (-b^2+4 a c\right )^{3/2}}+\left (3 b^2-2 a c\right ) \log (a+x (b+c x))}{2 c^4} \]

input
Integrate[x/(c + a/x^2 + b/x)^2,x]
 
output
(-4*b*c*x + c^2*x^2 + (2*(2*a^3*c^2 + b^5*x + a*b^3*(b - 5*c*x) + a^2*b*c* 
(-4*b + 5*c*x)))/((b^2 - 4*a*c)*(a + x*(b + c*x))) + (2*b*(3*b^4 - 20*a*b^ 
2*c + 30*a^2*c^2)*ArcTan[(b + 2*c*x)/Sqrt[-b^2 + 4*a*c]])/(-b^2 + 4*a*c)^( 
3/2) + (3*b^2 - 2*a*c)*Log[a + x*(b + c*x)])/(2*c^4)
 
3.5.22.3 Rubi [A] (verified)

Time = 0.40 (sec) , antiderivative size = 186, normalized size of antiderivative = 0.95, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {1692, 1164, 1200, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x}{\left (\frac {a}{x^2}+\frac {b}{x}+c\right )^2} \, dx\)

\(\Big \downarrow \) 1692

\(\displaystyle \int \frac {x^5}{\left (a+b x+c x^2\right )^2}dx\)

\(\Big \downarrow \) 1164

\(\displaystyle \frac {x^4 (2 a+b x)}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}-\frac {\int \frac {x^3 (8 a+3 b x)}{c x^2+b x+a}dx}{b^2-4 a c}\)

\(\Big \downarrow \) 1200

\(\displaystyle \frac {x^4 (2 a+b x)}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}-\frac {\int \left (\frac {3 b x^2}{c}-\frac {\left (3 b^2-8 a c\right ) x}{c^2}+\frac {b \left (3 b^2-11 a c\right )}{c^3}-\frac {a b \left (3 b^2-11 a c\right )+\left (b^2-4 a c\right ) \left (3 b^2-2 a c\right ) x}{c^3 \left (c x^2+b x+a\right )}\right )dx}{b^2-4 a c}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {x^4 (2 a+b x)}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}-\frac {-\frac {b \left (30 a^2 c^2-20 a b^2 c+3 b^4\right ) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{c^4 \sqrt {b^2-4 a c}}-\frac {\left (b^2-4 a c\right ) \left (3 b^2-2 a c\right ) \log \left (a+b x+c x^2\right )}{2 c^4}+\frac {b x \left (3 b^2-11 a c\right )}{c^3}-\frac {x^2 \left (3 b^2-8 a c\right )}{2 c^2}+\frac {b x^3}{c}}{b^2-4 a c}\)

input
Int[x/(c + a/x^2 + b/x)^2,x]
 
output
(x^4*(2*a + b*x))/((b^2 - 4*a*c)*(a + b*x + c*x^2)) - ((b*(3*b^2 - 11*a*c) 
*x)/c^3 - ((3*b^2 - 8*a*c)*x^2)/(2*c^2) + (b*x^3)/c - (b*(3*b^4 - 20*a*b^2 
*c + 30*a^2*c^2)*ArcTanh[(b + 2*c*x)/Sqrt[b^2 - 4*a*c]])/(c^4*Sqrt[b^2 - 4 
*a*c]) - ((b^2 - 4*a*c)*(3*b^2 - 2*a*c)*Log[a + b*x + c*x^2])/(2*c^4))/(b^ 
2 - 4*a*c)
 

3.5.22.3.1 Defintions of rubi rules used

rule 1164
Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S 
ymbol] :> Simp[(d + e*x)^(m - 1)*(d*b - 2*a*e + (2*c*d - b*e)*x)*((a + b*x 
+ c*x^2)^(p + 1)/((p + 1)*(b^2 - 4*a*c))), x] + Simp[1/((p + 1)*(b^2 - 4*a* 
c))   Int[(d + e*x)^(m - 2)*Simp[e*(2*a*e*(m - 1) + b*d*(2*p - m + 4)) - 2* 
c*d^2*(2*p + 3) + e*(b*e - 2*d*c)*(m + 2*p + 2)*x, x]*(a + b*x + c*x^2)^(p 
+ 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && LtQ[p, -1] && GtQ[m, 1] && Int 
QuadraticQ[a, b, c, d, e, m, p, x]
 

rule 1200
Int[(((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))^(n_.))/((a_.) + (b_.)* 
(x_) + (c_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*((f + g* 
x)^n/(a + b*x + c*x^2)), x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && In 
tegersQ[n]
 

rule 1692
Int[(x_)^(m_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] 
 :> Int[x^(m + 2*n*p)*(c + b/x^n + a/x^(2*n))^p, x] /; FreeQ[{a, b, c, m, n 
}, x] && EqQ[n2, 2*n] && ILtQ[p, 0] && NegQ[n]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 
3.5.22.4 Maple [A] (verified)

Time = 0.17 (sec) , antiderivative size = 238, normalized size of antiderivative = 1.21

method result size
default \(-\frac {-\frac {1}{2} c \,x^{2}+2 b x}{c^{3}}+\frac {\frac {-\frac {b \left (5 a^{2} c^{2}-5 a \,b^{2} c +b^{4}\right ) x}{c \left (4 a c -b^{2}\right )}-\frac {a \left (2 a^{2} c^{2}-4 a \,b^{2} c +b^{4}\right )}{c \left (4 a c -b^{2}\right )}}{c \,x^{2}+b x +a}+\frac {\frac {\left (-8 a^{2} c^{2}+14 a \,b^{2} c -3 b^{4}\right ) \ln \left (c \,x^{2}+b x +a \right )}{2 c}+\frac {2 \left (11 c b \,a^{2}-3 a \,b^{3}-\frac {\left (-8 a^{2} c^{2}+14 a \,b^{2} c -3 b^{4}\right ) b}{2 c}\right ) \arctan \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right )}{\sqrt {4 a c -b^{2}}}}{4 a c -b^{2}}}{c^{3}}\) \(238\)
risch \(\text {Expression too large to display}\) \(1596\)

input
int(x/(c+a/x^2+b/x)^2,x,method=_RETURNVERBOSE)
 
output
-1/c^3*(-1/2*c*x^2+2*b*x)+1/c^3*((-b*(5*a^2*c^2-5*a*b^2*c+b^4)/c/(4*a*c-b^ 
2)*x-a/c*(2*a^2*c^2-4*a*b^2*c+b^4)/(4*a*c-b^2))/(c*x^2+b*x+a)+1/(4*a*c-b^2 
)*(1/2*(-8*a^2*c^2+14*a*b^2*c-3*b^4)/c*ln(c*x^2+b*x+a)+2*(11*c*b*a^2-3*a*b 
^3-1/2*(-8*a^2*c^2+14*a*b^2*c-3*b^4)*b/c)/(4*a*c-b^2)^(1/2)*arctan((2*c*x+ 
b)/(4*a*c-b^2)^(1/2))))
 
3.5.22.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 504 vs. \(2 (188) = 376\).

Time = 0.29 (sec) , antiderivative size = 1029, normalized size of antiderivative = 5.25 \[ \int \frac {x}{\left (c+\frac {a}{x^2}+\frac {b}{x}\right )^2} \, dx=\left [\frac {2 \, a b^{6} - 16 \, a^{2} b^{4} c + 36 \, a^{3} b^{2} c^{2} - 16 \, a^{4} c^{3} + {\left (b^{4} c^{3} - 8 \, a b^{2} c^{4} + 16 \, a^{2} c^{5}\right )} x^{4} - 3 \, {\left (b^{5} c^{2} - 8 \, a b^{3} c^{3} + 16 \, a^{2} b c^{4}\right )} x^{3} - {\left (4 \, b^{6} c - 33 \, a b^{4} c^{2} + 72 \, a^{2} b^{2} c^{3} - 16 \, a^{3} c^{4}\right )} x^{2} - {\left (3 \, a b^{5} - 20 \, a^{2} b^{3} c + 30 \, a^{3} b c^{2} + {\left (3 \, b^{5} c - 20 \, a b^{3} c^{2} + 30 \, a^{2} b c^{3}\right )} x^{2} + {\left (3 \, b^{6} - 20 \, a b^{4} c + 30 \, a^{2} b^{2} c^{2}\right )} x\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, c^{2} x^{2} + 2 \, b c x + b^{2} - 2 \, a c - \sqrt {b^{2} - 4 \, a c} {\left (2 \, c x + b\right )}}{c x^{2} + b x + a}\right ) + 2 \, {\left (b^{7} - 11 \, a b^{5} c + 41 \, a^{2} b^{3} c^{2} - 52 \, a^{3} b c^{3}\right )} x + {\left (3 \, a b^{6} - 26 \, a^{2} b^{4} c + 64 \, a^{3} b^{2} c^{2} - 32 \, a^{4} c^{3} + {\left (3 \, b^{6} c - 26 \, a b^{4} c^{2} + 64 \, a^{2} b^{2} c^{3} - 32 \, a^{3} c^{4}\right )} x^{2} + {\left (3 \, b^{7} - 26 \, a b^{5} c + 64 \, a^{2} b^{3} c^{2} - 32 \, a^{3} b c^{3}\right )} x\right )} \log \left (c x^{2} + b x + a\right )}{2 \, {\left (a b^{4} c^{4} - 8 \, a^{2} b^{2} c^{5} + 16 \, a^{3} c^{6} + {\left (b^{4} c^{5} - 8 \, a b^{2} c^{6} + 16 \, a^{2} c^{7}\right )} x^{2} + {\left (b^{5} c^{4} - 8 \, a b^{3} c^{5} + 16 \, a^{2} b c^{6}\right )} x\right )}}, \frac {2 \, a b^{6} - 16 \, a^{2} b^{4} c + 36 \, a^{3} b^{2} c^{2} - 16 \, a^{4} c^{3} + {\left (b^{4} c^{3} - 8 \, a b^{2} c^{4} + 16 \, a^{2} c^{5}\right )} x^{4} - 3 \, {\left (b^{5} c^{2} - 8 \, a b^{3} c^{3} + 16 \, a^{2} b c^{4}\right )} x^{3} - {\left (4 \, b^{6} c - 33 \, a b^{4} c^{2} + 72 \, a^{2} b^{2} c^{3} - 16 \, a^{3} c^{4}\right )} x^{2} + 2 \, {\left (3 \, a b^{5} - 20 \, a^{2} b^{3} c + 30 \, a^{3} b c^{2} + {\left (3 \, b^{5} c - 20 \, a b^{3} c^{2} + 30 \, a^{2} b c^{3}\right )} x^{2} + {\left (3 \, b^{6} - 20 \, a b^{4} c + 30 \, a^{2} b^{2} c^{2}\right )} x\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, c x + b\right )}}{b^{2} - 4 \, a c}\right ) + 2 \, {\left (b^{7} - 11 \, a b^{5} c + 41 \, a^{2} b^{3} c^{2} - 52 \, a^{3} b c^{3}\right )} x + {\left (3 \, a b^{6} - 26 \, a^{2} b^{4} c + 64 \, a^{3} b^{2} c^{2} - 32 \, a^{4} c^{3} + {\left (3 \, b^{6} c - 26 \, a b^{4} c^{2} + 64 \, a^{2} b^{2} c^{3} - 32 \, a^{3} c^{4}\right )} x^{2} + {\left (3 \, b^{7} - 26 \, a b^{5} c + 64 \, a^{2} b^{3} c^{2} - 32 \, a^{3} b c^{3}\right )} x\right )} \log \left (c x^{2} + b x + a\right )}{2 \, {\left (a b^{4} c^{4} - 8 \, a^{2} b^{2} c^{5} + 16 \, a^{3} c^{6} + {\left (b^{4} c^{5} - 8 \, a b^{2} c^{6} + 16 \, a^{2} c^{7}\right )} x^{2} + {\left (b^{5} c^{4} - 8 \, a b^{3} c^{5} + 16 \, a^{2} b c^{6}\right )} x\right )}}\right ] \]

input
integrate(x/(c+a/x^2+b/x)^2,x, algorithm="fricas")
 
output
[1/2*(2*a*b^6 - 16*a^2*b^4*c + 36*a^3*b^2*c^2 - 16*a^4*c^3 + (b^4*c^3 - 8* 
a*b^2*c^4 + 16*a^2*c^5)*x^4 - 3*(b^5*c^2 - 8*a*b^3*c^3 + 16*a^2*b*c^4)*x^3 
 - (4*b^6*c - 33*a*b^4*c^2 + 72*a^2*b^2*c^3 - 16*a^3*c^4)*x^2 - (3*a*b^5 - 
 20*a^2*b^3*c + 30*a^3*b*c^2 + (3*b^5*c - 20*a*b^3*c^2 + 30*a^2*b*c^3)*x^2 
 + (3*b^6 - 20*a*b^4*c + 30*a^2*b^2*c^2)*x)*sqrt(b^2 - 4*a*c)*log((2*c^2*x 
^2 + 2*b*c*x + b^2 - 2*a*c - sqrt(b^2 - 4*a*c)*(2*c*x + b))/(c*x^2 + b*x + 
 a)) + 2*(b^7 - 11*a*b^5*c + 41*a^2*b^3*c^2 - 52*a^3*b*c^3)*x + (3*a*b^6 - 
 26*a^2*b^4*c + 64*a^3*b^2*c^2 - 32*a^4*c^3 + (3*b^6*c - 26*a*b^4*c^2 + 64 
*a^2*b^2*c^3 - 32*a^3*c^4)*x^2 + (3*b^7 - 26*a*b^5*c + 64*a^2*b^3*c^2 - 32 
*a^3*b*c^3)*x)*log(c*x^2 + b*x + a))/(a*b^4*c^4 - 8*a^2*b^2*c^5 + 16*a^3*c 
^6 + (b^4*c^5 - 8*a*b^2*c^6 + 16*a^2*c^7)*x^2 + (b^5*c^4 - 8*a*b^3*c^5 + 1 
6*a^2*b*c^6)*x), 1/2*(2*a*b^6 - 16*a^2*b^4*c + 36*a^3*b^2*c^2 - 16*a^4*c^3 
 + (b^4*c^3 - 8*a*b^2*c^4 + 16*a^2*c^5)*x^4 - 3*(b^5*c^2 - 8*a*b^3*c^3 + 1 
6*a^2*b*c^4)*x^3 - (4*b^6*c - 33*a*b^4*c^2 + 72*a^2*b^2*c^3 - 16*a^3*c^4)* 
x^2 + 2*(3*a*b^5 - 20*a^2*b^3*c + 30*a^3*b*c^2 + (3*b^5*c - 20*a*b^3*c^2 + 
 30*a^2*b*c^3)*x^2 + (3*b^6 - 20*a*b^4*c + 30*a^2*b^2*c^2)*x)*sqrt(-b^2 + 
4*a*c)*arctan(-sqrt(-b^2 + 4*a*c)*(2*c*x + b)/(b^2 - 4*a*c)) + 2*(b^7 - 11 
*a*b^5*c + 41*a^2*b^3*c^2 - 52*a^3*b*c^3)*x + (3*a*b^6 - 26*a^2*b^4*c + 64 
*a^3*b^2*c^2 - 32*a^4*c^3 + (3*b^6*c - 26*a*b^4*c^2 + 64*a^2*b^2*c^3 - 32* 
a^3*c^4)*x^2 + (3*b^7 - 26*a*b^5*c + 64*a^2*b^3*c^2 - 32*a^3*b*c^3)*x)*...
 
3.5.22.6 Sympy [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 1012 vs. \(2 (180) = 360\).

Time = 1.35 (sec) , antiderivative size = 1012, normalized size of antiderivative = 5.16 \[ \int \frac {x}{\left (c+\frac {a}{x^2}+\frac {b}{x}\right )^2} \, dx=- \frac {2 b x}{c^{3}} + \left (- \frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right ) \log {\left (x + \frac {16 a^{3} c^{2} - 17 a^{2} b^{2} c + 16 a^{2} c^{5} \left (- \frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right ) + 3 a b^{4} - 8 a b^{2} c^{4} \left (- \frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right ) + b^{4} c^{3} \left (- \frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right )}{30 a^{2} b c^{2} - 20 a b^{3} c + 3 b^{5}} \right )} + \left (\frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right ) \log {\left (x + \frac {16 a^{3} c^{2} - 17 a^{2} b^{2} c + 16 a^{2} c^{5} \left (\frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right ) + 3 a b^{4} - 8 a b^{2} c^{4} \left (\frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right ) + b^{4} c^{3} \left (\frac {b \sqrt {- \left (4 a c - b^{2}\right )^{3}} \cdot \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right )}{2 c^{4} \cdot \left (64 a^{3} c^{3} - 48 a^{2} b^{2} c^{2} + 12 a b^{4} c - b^{6}\right )} - \frac {2 a c - 3 b^{2}}{2 c^{4}}\right )}{30 a^{2} b c^{2} - 20 a b^{3} c + 3 b^{5}} \right )} + \frac {- 2 a^{3} c^{2} + 4 a^{2} b^{2} c - a b^{4} + x \left (- 5 a^{2} b c^{2} + 5 a b^{3} c - b^{5}\right )}{4 a^{2} c^{5} - a b^{2} c^{4} + x^{2} \cdot \left (4 a c^{6} - b^{2} c^{5}\right ) + x \left (4 a b c^{5} - b^{3} c^{4}\right )} + \frac {x^{2}}{2 c^{2}} \]

input
integrate(x/(c+a/x**2+b/x)**2,x)
 
output
-2*b*x/c**3 + (-b*sqrt(-(4*a*c - b**2)**3)*(30*a**2*c**2 - 20*a*b**2*c + 3 
*b**4)/(2*c**4*(64*a**3*c**3 - 48*a**2*b**2*c**2 + 12*a*b**4*c - b**6)) - 
(2*a*c - 3*b**2)/(2*c**4))*log(x + (16*a**3*c**2 - 17*a**2*b**2*c + 16*a** 
2*c**5*(-b*sqrt(-(4*a*c - b**2)**3)*(30*a**2*c**2 - 20*a*b**2*c + 3*b**4)/ 
(2*c**4*(64*a**3*c**3 - 48*a**2*b**2*c**2 + 12*a*b**4*c - b**6)) - (2*a*c 
- 3*b**2)/(2*c**4)) + 3*a*b**4 - 8*a*b**2*c**4*(-b*sqrt(-(4*a*c - b**2)**3 
)*(30*a**2*c**2 - 20*a*b**2*c + 3*b**4)/(2*c**4*(64*a**3*c**3 - 48*a**2*b* 
*2*c**2 + 12*a*b**4*c - b**6)) - (2*a*c - 3*b**2)/(2*c**4)) + b**4*c**3*(- 
b*sqrt(-(4*a*c - b**2)**3)*(30*a**2*c**2 - 20*a*b**2*c + 3*b**4)/(2*c**4*( 
64*a**3*c**3 - 48*a**2*b**2*c**2 + 12*a*b**4*c - b**6)) - (2*a*c - 3*b**2) 
/(2*c**4)))/(30*a**2*b*c**2 - 20*a*b**3*c + 3*b**5)) + (b*sqrt(-(4*a*c - b 
**2)**3)*(30*a**2*c**2 - 20*a*b**2*c + 3*b**4)/(2*c**4*(64*a**3*c**3 - 48* 
a**2*b**2*c**2 + 12*a*b**4*c - b**6)) - (2*a*c - 3*b**2)/(2*c**4))*log(x + 
 (16*a**3*c**2 - 17*a**2*b**2*c + 16*a**2*c**5*(b*sqrt(-(4*a*c - b**2)**3) 
*(30*a**2*c**2 - 20*a*b**2*c + 3*b**4)/(2*c**4*(64*a**3*c**3 - 48*a**2*b** 
2*c**2 + 12*a*b**4*c - b**6)) - (2*a*c - 3*b**2)/(2*c**4)) + 3*a*b**4 - 8* 
a*b**2*c**4*(b*sqrt(-(4*a*c - b**2)**3)*(30*a**2*c**2 - 20*a*b**2*c + 3*b* 
*4)/(2*c**4*(64*a**3*c**3 - 48*a**2*b**2*c**2 + 12*a*b**4*c - b**6)) - (2* 
a*c - 3*b**2)/(2*c**4)) + b**4*c**3*(b*sqrt(-(4*a*c - b**2)**3)*(30*a**2*c 
**2 - 20*a*b**2*c + 3*b**4)/(2*c**4*(64*a**3*c**3 - 48*a**2*b**2*c**2 +...
 
3.5.22.7 Maxima [F(-2)]

Exception generated. \[ \int \frac {x}{\left (c+\frac {a}{x^2}+\frac {b}{x}\right )^2} \, dx=\text {Exception raised: ValueError} \]

input
integrate(x/(c+a/x^2+b/x)^2,x, algorithm="maxima")
 
output
Exception raised: ValueError >> Computation failed since Maxima requested 
additional constraints; using the 'assume' command before evaluation *may* 
 help (example of legal syntax is 'assume(4*a*c-b^2>0)', see `assume?` for 
 more deta
 
3.5.22.8 Giac [A] (verification not implemented)

Time = 0.33 (sec) , antiderivative size = 188, normalized size of antiderivative = 0.96 \[ \int \frac {x}{\left (c+\frac {a}{x^2}+\frac {b}{x}\right )^2} \, dx=-\frac {{\left (3 \, b^{5} - 20 \, a b^{3} c + 30 \, a^{2} b c^{2}\right )} \arctan \left (\frac {2 \, c x + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{{\left (b^{2} c^{4} - 4 \, a c^{5}\right )} \sqrt {-b^{2} + 4 \, a c}} + \frac {{\left (3 \, b^{2} - 2 \, a c\right )} \log \left (c x^{2} + b x + a\right )}{2 \, c^{4}} + \frac {c^{2} x^{2} - 4 \, b c x}{2 \, c^{4}} + \frac {a b^{4} - 4 \, a^{2} b^{2} c + 2 \, a^{3} c^{2} + {\left (b^{5} - 5 \, a b^{3} c + 5 \, a^{2} b c^{2}\right )} x}{{\left (c x^{2} + b x + a\right )} {\left (b^{2} - 4 \, a c\right )} c^{4}} \]

input
integrate(x/(c+a/x^2+b/x)^2,x, algorithm="giac")
 
output
-(3*b^5 - 20*a*b^3*c + 30*a^2*b*c^2)*arctan((2*c*x + b)/sqrt(-b^2 + 4*a*c) 
)/((b^2*c^4 - 4*a*c^5)*sqrt(-b^2 + 4*a*c)) + 1/2*(3*b^2 - 2*a*c)*log(c*x^2 
 + b*x + a)/c^4 + 1/2*(c^2*x^2 - 4*b*c*x)/c^4 + (a*b^4 - 4*a^2*b^2*c + 2*a 
^3*c^2 + (b^5 - 5*a*b^3*c + 5*a^2*b*c^2)*x)/((c*x^2 + b*x + a)*(b^2 - 4*a* 
c)*c^4)
 
3.5.22.9 Mupad [B] (verification not implemented)

Time = 8.69 (sec) , antiderivative size = 382, normalized size of antiderivative = 1.95 \[ \int \frac {x}{\left (c+\frac {a}{x^2}+\frac {b}{x}\right )^2} \, dx=\frac {x^2}{2\,c^2}-\frac {\frac {a\,\left (2\,a^2\,c^2-4\,a\,b^2\,c+b^4\right )}{c\,\left (4\,a\,c-b^2\right )}+\frac {b\,x\,\left (5\,a^2\,c^2-5\,a\,b^2\,c+b^4\right )}{c\,\left (4\,a\,c-b^2\right )}}{c^4\,x^2+b\,c^3\,x+a\,c^3}-\frac {\ln \left (c\,x^2+b\,x+a\right )\,\left (128\,a^4\,c^4-288\,a^3\,b^2\,c^3+168\,a^2\,b^4\,c^2-38\,a\,b^6\,c+3\,b^8\right )}{2\,\left (64\,a^3\,c^7-48\,a^2\,b^2\,c^6+12\,a\,b^4\,c^5-b^6\,c^4\right )}-\frac {2\,b\,x}{c^3}+\frac {b\,\mathrm {atan}\left (\frac {c^4\,\left (\frac {2\,b\,x\,\left (30\,a^2\,c^2-20\,a\,b^2\,c+3\,b^4\right )}{c^3\,{\left (4\,a\,c-b^2\right )}^3}-\frac {b\,\left (b^3\,c^3-4\,a\,b\,c^4\right )\,\left (30\,a^2\,c^2-20\,a\,b^2\,c+3\,b^4\right )}{c^7\,{\left (4\,a\,c-b^2\right )}^4}\right )\,{\left (4\,a\,c-b^2\right )}^{5/2}}{30\,a^2\,b\,c^2-20\,a\,b^3\,c+3\,b^5}\right )\,\left (30\,a^2\,c^2-20\,a\,b^2\,c+3\,b^4\right )}{c^4\,{\left (4\,a\,c-b^2\right )}^{3/2}} \]

input
int(x/(c + a/x^2 + b/x)^2,x)
 
output
x^2/(2*c^2) - ((a*(b^4 + 2*a^2*c^2 - 4*a*b^2*c))/(c*(4*a*c - b^2)) + (b*x* 
(b^4 + 5*a^2*c^2 - 5*a*b^2*c))/(c*(4*a*c - b^2)))/(a*c^3 + c^4*x^2 + b*c^3 
*x) - (log(a + b*x + c*x^2)*(3*b^8 + 128*a^4*c^4 + 168*a^2*b^4*c^2 - 288*a 
^3*b^2*c^3 - 38*a*b^6*c))/(2*(64*a^3*c^7 - b^6*c^4 + 12*a*b^4*c^5 - 48*a^2 
*b^2*c^6)) - (2*b*x)/c^3 + (b*atan((c^4*((2*b*x*(3*b^4 + 30*a^2*c^2 - 20*a 
*b^2*c))/(c^3*(4*a*c - b^2)^3) - (b*(b^3*c^3 - 4*a*b*c^4)*(3*b^4 + 30*a^2* 
c^2 - 20*a*b^2*c))/(c^7*(4*a*c - b^2)^4))*(4*a*c - b^2)^(5/2))/(3*b^5 + 30 
*a^2*b*c^2 - 20*a*b^3*c))*(3*b^4 + 30*a^2*c^2 - 20*a*b^2*c))/(c^4*(4*a*c - 
 b^2)^(3/2))